If $\alpha = 0.98$ and the current through the emitter $i_e = 20 \, mA$,the value of $\beta$ is

In an $n-p-n$ transistor amplifier,the collector current is $9 \ mA$. If $90 \%$ of the electrons emitted reach the collector,then

$A$ $n-p-n$ transistor is connected in common-emitter configuration in which the collector supply is $8\, V$ and the voltage drop across the load resistance of $800\,\Omega$ connected in the collector circuit is $0.8\, V$. If the current amplification factor $\alpha$ is $25/26$,the collector-emitter voltage $V_{CE}$ and the base current $I_B$ will be:

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is

In a common emitter amplifier,the output resistance is $5000 \Omega$ and the input resistance is $2000 \Omega$. If the peak value of input signal voltage is $100 mV$ and $\beta=50$,then the peak value of output voltage is

In an experiment,the input characteristics are shown for a $CE$ configuration $n-p-n$ transistor for different output voltages. Based on the graph,which of the following is correct?